SODIUM BROMIDE NaBr

Properties of sodium bromide NaBr:

White. It melts without decomposition. Readily soluble in water (no hydrolysis). Reducer.


Obtaining sodium bromide NaBr:

2 Na + E2 = 2NaE (normal temp., Е = F, Cl, Вr, I).

6 NaOH + 3 Br2 + 2(NH3-H2O) →(time) 6 NaBr + N2↑ + 8H2O (normal temp.).

2 NaI (cold) + E2 = 2NaE + I2↓ (E = Cl, Br)

NaI (hot) + 3 H2O + 3Cl2 = NaIO3 + 6HCl.


Reactions with sodium bromide NaBr:

NaBr-2H2O = NaBr + 2H2O (t> 51° C, vacuum).

NaBr (diluted) + 4 H2O = [Na(H2O)4](+) + Br(-) (pH 7).

2 NaBr (solid) + H2SO4 (conc. 10-50%, cold) = Na2SO4 + 2HBr

2 NaBr (solid) + 3 H2SO4 (conc.>50%, hot) = 2 NaHSO4 + Br2 + SO2 + 2H2O.

2 NaBr (hot) + Cl2 = 2 NaCl + Br2↑.

5 NaBr + 3 H2SO4(diluted) + NaBrO3 = 3Br2 + 3Na2SO4 + 3H2O

2 NaBr + 2 H2SO4 (conc.) + MnO2 = Br2 + Na2SO4 + MnSO4 + 2H2O (boiling).

NaBr + 3 H2O →Electrolysis→ 3H2↑ (cathode) + NaBrO3 (anode).


 

Did you know?

There are 4 basic reactions: single replacement, double replacement, synthesis and decomposition.